Azimuthal quantum number is $I = 1 - P$ subshell

$P$ subshell has $3$ orbitals. each can hold two electrons.

So, Number of orbitals present can be calculated by the formula $(2 l+1)$

Here value of $I =1,$

Hence Number of orbitals $=2 \times 1+1=3$

$3 p \rightarrow$

$\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$

The $p$ subshell has maximum of $3$ orbitals Hence total of $6\, electrons$ can fit for $n=3$ and $l=1$