MCQ
$n-$pentane and iso pentane can be distinguished by
- A$B{r_2}$
- B${O_3}$
- Cconc. ${H_2}S{O_4}$
- ✓$KMn{O_4}$
✓
Answer
Correct option: D.
$KMn{O_4}$
d
(d) On oxidation, with $KMn{O_4}$, they give different alcohols
(d) On oxidation, with $KMn{O_4}$, they give different alcohols
$\mathop {C{H_3}C{H_2}C{H_2}C{H_2}C{H_3}}\limits_{n{\text{ }}penten} \mathop {\xrightarrow{{KMn{O_4}}}}\limits_{[O]} $ $\mathop {C{H_3}C{H_2}C{H_2}C{H_2}CHO{H_2}}\limits_{{\text{1}}^\circ {\text{ }}alcohol} $
$C{H_3}C{H_2} - \mathop {\mathop {{\text{ }}C}\limits_| H}\limits_{C{H_3}} - C{H_3}\mathop {\xrightarrow{{KMn{O_4}}}}\limits_{[O]} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,OH} \\
{\,\,\,\,\,\,\,\,|} \\
{C{H_3}C{H_2} - C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{{3^o}\,alcohol} $
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