$n$ the rectangle, shown below, the two corners have charges ${q_1} = - 5\,\mu C$ and ${q_2} = + 2.0\,\mu C$. The work done in moving a charge $ + 3.0\,\mu C$ from $B$ to $A$ is.........$J$ $(1/4\pi {\varepsilon _0} = {10^{10}}\,N{\rm{ - }}{m^2}/{C^2})$
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(a) Work done $W = 3 \times {10^{ - 6}}({V_A} - {V_B});$ where
${V_A} = {10^{10}}\left[ {\frac{{( - 5 \times {{10}^{ - 6}})}}{{15 \times {{10}^{ - 2}}}} + \frac{{2 \times {{10}^{ - 6}}}}{{5 \times {{10}^{ - 2}}}}} \right] = \frac{1}{{15}} \times {10^6}\,volt$
and ${V_B} = {10^{10}}\left[ {\frac{{(2 \times {{10}^{ - 6}})}}{{15 \times {{10}^{ - 2}}}} - \frac{{5 \times {{10}^{ - 6}}}}{{5 \times {{10}^{ - 2}}}}} \right] = - \frac{{13}}{{15}} \times {10^6}\,volt$
 $W = 3 \times {10^{ - 6}}\left[ {\frac{1}{{15}} \times {{10}^6} - \left( { - \frac{{13}}{{15}} \times {{10}^6}} \right)} \right]= 2.8 \,J$
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