(n+1)C1 + (n+1)C2 + (n+1)C3 +…..+ (n+1)Cn = - Vidyadip

MCQ

⁽ⁿ⁺¹⁾C₁ + ⁽ⁿ⁺¹⁾C₂ + ⁽ⁿ⁺¹⁾C₃ +…..+ ⁽ⁿ⁺¹⁾C_n =

A
2(2ⁿ+1)
B
2(2ⁿ−1)
C
2ⁿ⁺¹
D
(2ⁿ⁺¹ - 1)

✓

Answer

2(2ⁿ−1)

Solution

As in the hint required expression + ⁿ⁺¹C₀+ ⁿ⁺¹C_n+1= 2ⁿ⁺¹

⇒ required. expression = 2ⁿ⁺¹− 2 = 2(2ⁿ−1)

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