$2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$
જો બંધ પાત્રમાં $0.1 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{NO}_{(\mathrm{g})}$ લેવામાં આવે તો, સંતુલન ૫૨ $\mathrm{NO}_{(\mathrm{g})}$ નો વિયોજન અંશ $(\alpha)$ શું થશે?
$\mathrm{K}_{\mathrm{c}} $$ =\frac{\left[\mathrm{N}_2\right]\left[\mathrm{O}_2\right]}{[\mathrm{NO}]^2} $
$ =\frac{3 \times 10^{-3} \times 4.2 \times 10^{-3}}{2.8 \times 10^{-3} \times 2.8 \times 10^{-3}} $
$ =1.607$
$2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} $
$\mathrm{t}=0 $
$0.1 \quad 0 \quad 0 $
$0.1-0.1 \alpha \quad 0.05 \alpha \quad 0.05 \alpha $
$\mathrm{K}_{\mathrm{c}}=\frac{0.05 \alpha \times 0.05 \alpha}{(0.1-0.1 \alpha)^2} $
$\mathrm{~K}_{\mathrm{c}}=\frac{0.05 \alpha \times 0.05 \alpha}{0.01(1-\alpha)^2} $
$1.607=\frac{(0.05)^2 \alpha^2}{0.01(1-\alpha)^2} $
$\frac{\alpha^2}{(1-\alpha)^2}=\frac{1.607 \times(0.1)^2}{(0.05)^2} $
$\frac{\alpha}{1-\alpha}=\frac{1.27 \times 0.1}{0.05} $
$\frac{\alpha}{1-\alpha}=2.54 $
$\alpha=2.54-2.54 \alpha $
$3.54 \alpha=2.54 $
$\alpha=\frac{2.54}{3.54}=0.717$
$NO_{(g)} + \frac{1}{2}{O_2} \rightleftharpoons N{O_2}_{(g)}$
$2N{O_2}_{(g)} \rightleftharpoons 2NO_{(g)} + {O_2}_{(g)}$