MCQ
$N{a_2}{S_2}{O_3} + {I_2} \to $ Product is
- A$N{a_2}S$
- B$NaI$
- ✓$N{a_2}{S_4}{O_6}$
- D${S_2}$
✓
Answer
Correct option: C.
$N{a_2}{S_4}{O_6}$
c
(c)$2N{a_2}{S_2}{O_3} + {I_2} \to 2NaI + N{a_2}{S_4}{O_6}$.
(c)$2N{a_2}{S_2}{O_3} + {I_2} \to 2NaI + N{a_2}{S_4}{O_6}$.
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