b $(b)$ On the basis that the rate determining step is the formation of the carbonium ion, then, with benzene as the reference compound, the rate is faster when the substituent activates the ring ( $+I $and $I$ or $+R ; o/ p$) and the rate is slower when the substituent deactivates the ring ($-I$ and $I$ or $- R ; m$). Halogen is an exception; it deactivates the ring $(-I, + R ; - I > +R)$, but the orientation is $o/ p.$ Hence, the order of increasing rate of nitration is :
$PhNO_2 < PhCl < PhH = C_6D_6 < PhMe$
$(-I, -R)$ $(-I, -R ; -I > +R)$ $(+I)$
Since proton removal from the carbonium ion is fast, no kinetic isotope -effect is observed when $H$ is replaced by $D$. Hence, the rates of nitration of $PhH$ and $C_6D_6$ are the same. Had a kinetic isotope effect been observed, this would mean that the second step had now become rate determining.
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એક કાર્બનિક સંયોજન $(C_3H_9N)\,\, (A),$ જ્યારે નાઇટ્રસ એસિડની પ્રકિયા કરવામાં આવે ત્યારે આલ્કોહોલ આપવામાં આવે છે અને $N_2$ ગેસ મુક્ત થયો. $(A)$ $CHCl_3$ અને કોસ્ટિક પોટાશ સાથે $(C)$ સાથે ગરમ કરીને આઈસોપ્રોપાઇલમિથાઇલએમાઈન આપે છે તો $(A)$ નું બંધારણ શું હશે ?