$\mathrm{HNO}_{3}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{H}_{2} \mathrm{NO}_{3}^{+}+\mathrm{HSO}_{4}^{-}$
$\mathrm{H}_{2} \mathrm{NO}_{3}^{+} \rightarrow \mathrm{NO}_{2}^{+}+\mathrm{H}_{2} \mathrm{O}$
Hence, in this reaction HNO $_{3}$ acts as a base and $\mathrm{H}_{2} \mathrm{SO}_{4}$ as an acid.
ટોલ્યુઇન, નાઈટ્રોબેન્ઝીન, ઝાયલીન, ક્યુમીન, એનીલીન, ક્લોરોબેન્ઝીન, $m$નાઈટ્રોએનીલીન, $m-$ડાયનાઈટ્રોબેન્ઝીન
${C_6}{H_5}N{O_2}\xrightarrow{{Sn / HCl}}X\xrightarrow{{{C_6}{H_5}COCl}}Y + HCl$
$Y$ શું હશે ?