Question
Name two scales of temperature. How are they inter-related?
✓
Answer
Two scales of temperature are
(i) Celsius (ii) Fahrenheit Relation:
Water Freezes at $0^{\circ} \mathrm{C}$ or $32^{\circ} \mathrm{F}$ and boils at $100^{\circ} \mathrm{C}$ or $212^{\circ} \mathrm{F}$
$
\begin{aligned}
& \therefore(212-32)^{\circ} \mathrm{F}=(100-0)^{\circ} \mathrm{C} \\
& 180^{\circ} \mathrm{F}=100^{\circ} \mathrm{C} \\
& 1^{\circ} \mathrm{F}=\left(\frac{5}{9}\right){ }^{\circ} \mathrm{C}
\end{aligned}
$
or $1^{\circ} \mathrm{C}=\left(\frac{9}{5}\right){ }^{\circ} \mathrm{F}$
or $\frac{C-0}{100-0}=\frac{F-32}{212-32}$
or $\frac{C}{100}=\frac{F-32}{180}$
or $\frac{\mathrm{C}}{5}=\frac{\mathrm{F}-32}{9}$
(i) Celsius (ii) Fahrenheit Relation:
Water Freezes at $0^{\circ} \mathrm{C}$ or $32^{\circ} \mathrm{F}$ and boils at $100^{\circ} \mathrm{C}$ or $212^{\circ} \mathrm{F}$
$
\begin{aligned}
& \therefore(212-32)^{\circ} \mathrm{F}=(100-0)^{\circ} \mathrm{C} \\
& 180^{\circ} \mathrm{F}=100^{\circ} \mathrm{C} \\
& 1^{\circ} \mathrm{F}=\left(\frac{5}{9}\right){ }^{\circ} \mathrm{C}
\end{aligned}
$
or $1^{\circ} \mathrm{C}=\left(\frac{9}{5}\right){ }^{\circ} \mathrm{F}$
or $\frac{C-0}{100-0}=\frac{F-32}{212-32}$
or $\frac{C}{100}=\frac{F-32}{180}$
or $\frac{\mathrm{C}}{5}=\frac{\mathrm{F}-32}{9}$
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