MCQ
Natural glucose is termed $D-$ glucose because
  • A
    $- OH$ on the second carbon is on the right side in Fischer projection
  • B
    $- OH$ on the sixth carbon is on the right side in Fischer projection
  • $- OH$ on the fifth carbon is on the right side in Fischer projection
  • D
    It is dextrorotatory

Answer

Correct option: C.
$- OH$ on the fifth carbon is on the right side in Fischer projection
c
Fisher gave the prefix $'D''$ to compounds whosebottom chiral hasits $OH$ to the right. So natural glucoseis called $D\,-$ glucose is called $D\,-$ glucose or dextrose.

Structure of $D\,-$ glucose :

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

In the reaction given below
The products formed in the reaction of cumene with $O_2$ followed by treatment with dil. $HCl$ are
Which of the following has second ionisation potential less than expected
The minimum energy required for molecules to enter into the reaction is called
Which one of the following statements for the order of a reaction is incorrect?
When $100 \ mL$ of $1.0 \ M \ HCl$ was mixed with $100 \ mL$ of $1.0 \ M \ NaOH$ in an insulated beaker at constant pressure, a temperature increase of $5.7^{\circ} C$ was measured for the beaker and its contents (Expt. $1$). Because the enthalpy of neutralization of a strong acid with a strong base is a constant $\left(-57.0 \ kJ \ mol ^{-1}\right)$, this experiment could be used to measure the calorimeter constant. In a second experiment (Expt. $2$), $100 \ mL$ of $2.0 \ M$ acetic acid $\left(K_a=2.0 \times 10^{-5}\right)$ was mixed with $100 \ mL$ of $1.0 M \ NaOH$ (under identical conditions to Expt. $1$) where a temperature rise of $5.6^{\circ} C$ was measured.

(Consider heat capacity of all solutions as $4.2 J g ^{-1} K ^{-1}$ and density of all solutions as $1.0 \ g mL ^{-1}$ )

$1.$ Enthalpy of dissociation (in $kJ mol ^{-1}$ ) of acetic acid obtained from the Expt. $2$ is

$(A)$ $1.0$ $(B)$ $10.0$ $(C)$ $24.5$ $(D)$ $51.4$

$2.$ The $pH$ of the solution after Expt. $2$ is

$(A)$ $2.8$ $(B)$ $4.7$ $(C)$ $5.0$ $(D)$ $7.0$

Give the answer question $1$ and $2.$

Identify the which can exhibit tautomerism ?
The $IUPAC$ name of $\begin{matrix}
   \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O  \\
   \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||  \\
   C{{H}_{3}}-CH=CH-C-OH  \\
\end{matrix}$ is
The equilibrium constant for the reaction ${N_2} + 3{H_2}$ $\rightleftharpoons$ $2N{H_3}$ is $K,$ then the equilibrium constant for the equilibrium $N{H_3}$ $\rightleftharpoons$ $\frac{1}{2}{N_2} + \frac{3}{2}{H_2}$ is
Water is oxidised to oxygen by