MCQ
Nesseler's reagent is
- A${K_2}Hg{I_4}$
- ✓${K_2}Hg{I_4} + KOH$
- C${K_2}Hg{I_2} + KOH$
- D${K_2}Hg{I_4} + Hg$
✓
Answer
Correct option: B.
${K_2}Hg{I_4} + KOH$
(b)$2KI + Hg{I_2} \to \mathop {{K_2}Hg{l_4} + KOH}\limits_{\atop\{\rm{Nessler's reagent}}\} $
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