MCQ
The ${K_c}$ for ${H_{2(g)}} + {I_{2(g)}}$ $\rightleftharpoons$ $2H{I_{(g)}}$ is $64$. If the volume of the container is reduced to one-half of its original volume, the value of the equilibrium constant will be
- A$28$
- ✓$64$
- C$32$
- D$16$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(A)$ $n=3,1=0, m=0$
$(B)$ $n=4,1=0, m=0$
$(C)$ $n =3,1=1, m =0$
$(D)$ $n=3,1=2, m=1$

