MCQ
The ${K_c}$ for ${H_{2(g)}} + {I_{2(g)}}$ $\rightleftharpoons$ $2H{I_{(g)}}$ is $64$. If the volume of the container is reduced to one-half of its original volume, the value of the equilibrium constant will be
  • A
    $28$
  • $64$
  • C
    $32$
  • D
    $16$

Answer

Correct option: B.
$64$
(b) ${K_c}$ does not depend upon initial concentration of reactants or product.

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