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STD 12 - p -Block elements - ll — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 12 - p -Block elements - ll4 Marks
MCQ
$(NH_4)_2Cr_2O_7$ on heating gives :
  • A
    $ N_2O$
  • B
    $NH_3$
  • C
    $NO_2$
  • D
    $N_2$
✓

Answer

On heating, $\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ gives, nitrogen gas.$\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \rightarrow \mathrm{N}_{2}+\mathrm{Cr}_{2} \mathrm{O}_{3}+4 \mathrm{H}_{2} \mathrm{O}$
$($Orange$) ($Green$)$
But whenever, $\mathrm{NH}_{4} \mathrm{NO}_{2}$ and $\mathrm{NH}_{4} \mathrm{NO}_{3}$ heated, then nitrogen and nitrogen dioxide gas liberated.
$\mathrm{NH}_{4} \mathrm{NO}_{2} \rightarrow \mathrm{N}_{2}+2 \mathrm{H}_{2} \mathrm{O}$
$\mathrm{NH}_{4} \mathrm{NO}_{3} \rightarrow \mathrm{N}_{2} \mathrm{O}+2 \mathrm{H}_{2} \mathrm{O}$
So, the correct option is $\mathrm{D}$

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