$Image$
- Step$-l$ is $\mathrm{S}_{\mathrm{N}}$ reaction with $\stackrel{\ominus}{\mathrm{C}} \mathrm{N}$ nucleophile.
- Step$-Il$ will give amide.
- Step$-III$ is Hoffmann bromamide degradation reaction.
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$\mathop {C{H_3} - C{H_2} - N{H_2}}\limits_{\mathop 2\limits } \,$$\,\mathop {{{(C{H_3})}_2}NH}\limits_{\mathop 3\limits } $
$\mathop {C{H_3} - \mathop {\mathop C\limits^{||} }\limits^O - N{H_2}}\limits_4 $
$C{H_3}C{H_2}COOH\xrightarrow{{SOC{l_2}}}\,B\,$$ \xrightarrow{{N{H_3}}}\,C\,\xrightarrow[{B{r_2}}]{{KOH}}\,D$
$D$ નું બંધારણ શું હશે ?