b
Bond order \(=\frac{1}{2}\) [Number of bonding electrons \(-\) Number of anti bonding electrons]

\(I)\) Bond order of \(H _2^{-}=\frac{1}{2}[2-1]=0.5\)

Bond order of \(H _2^{+}=\frac{1}{2}[1-0]=0.5\)

Bond order of \(H _2=\frac{1}{2}[2-0]=1\)

Bond order of \(H _2\) is greater than \(H _2^{-}\)and \(H _2^{+}\)

\(II)\) Bond order of \(O _2^{+}=\frac{1}{2}[10-5]=2.5\)

Bond order of \(NO =\frac{1}{2}[10-5]=2.5\)

Bond order of \(N _2^{-}=\frac{1}{2}[10-5]=2.5\)

\(III)\) Bond order can have any value. And a bond order equal to zero implies

that there is no bond at all between the atoms.

\(IV) \,NO _3^{-}\)and \(BO _3^{-}\) do not have same bond order.