Since acid chloride is more reactive than alkyl halide \(-\,COCl\) group will react first.
In the second step, Friedel craft's alkylation occurs in a position that is ortho to alkoxy group and para to methoxy group. Both mahoxy and alkoxy groups are ortho para directing group.
$(i) \,\,\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CH - C{H_3}} \\
{\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,OH}
\end{array}\,\xrightarrow{{{H^ + }/heat}}\,\,\mathop A\limits_{[Major\,product]} \, + \,\mathop B\limits_{[Minor\,product]} $
$(ii)\,\, A\xrightarrow[{in\,\,absence\,\,\,of\,peroxide}]{{HBr,\,dark}}\,\,\mathop C\limits_{[Major\,product]} \, + \,\mathop D\limits_{[Minor\,product]} $
મુખ્ય નીપજ $(A)$ અને $(C)$ અનુક્રમે શું હશે ?