
$\mathrm{Ph}-\mathrm{CH}=\mathrm{CH}_2 \xrightarrow[\text { (iii) } \mathrm{HBr}{(iv) \mathrm{Mg}, ether, then \mathrm{HCHO} / \mathrm{H}_3 \mathrm{O}^{+}}]{{(i)BH_3}{\text { (ii) } \mathrm{H}_2 \mathrm{O}_2,{ }^{\text {(-) }} \mathrm{OH}}} \mathrm{A}$
(નજીકના પૂર્ણાંક સુધી રાઉન્ડ) [આપેલ : આણ્વિય દળ : $C =12.0 \,u , H : 1.0\, u,O : 16.0 \,u , Br =80.0 \,u ]$
