All the carbon atoms are \(s{p^3}\) hybridized.
$\begin{array}{*{20}{c}}
{Me} \\
{|\,\,\,\,} \\
{{H_2}C - N - C - Et} \\
{\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,|\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Me\,\,\,\,\,C{H_2}C{H_3}}
\end{array}$
$\begin{array}{*{20}{c}}
{C{H_2} - C = CH - C - N{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{N{H_2}\,\,\,\,\,\,\,\,\,\,OC{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$CH _{2} = C = C H - C H _{3}$
$\quad 1\quad \quad 2\quad \quad 3\quad \quad \quad 4$
અણુમાં, કાર્બન $1,2,3$ અને $4$નું સંકરણ અનુક્રમે શોધો.
$(i)$ $C{H_3}C{H_2}C{H_2}C{H_3}$
$(ii)$ $C{H_3} - CH = CH - C{H_3}$
$(iii)$ $C{H_2} = CH - CH = C{H_2}$
$(iv)$ $H - C \equiv C - H$