\((2)\)\(\begin{array}{*{20}{c}} {C{H_3} - CH - Br\,\xrightarrow[{{S_{{N^2}}}}]{{\mathop O\limits^ \ominus H}}} \\ {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {ph\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}\)\(\begin{array}{*{20}{c}} {ph - CH - OH} \\ {|\,\,\,\,\,\,\,\,} \\ {C{H_3}} \end{array}\)
\((4)\)\(\begin{array}{*{20}{c}} {C{H_3} - CH - Br\,\xrightarrow[{{S_{{N^2}}}}]{{\mathop O\limits^ \ominus H}}} \\ {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {{C_6}{H_{13}\,\,\,\,\,\,}} \end{array}\)\(\begin{array}{*{20}{c}} {C{H_3} - CH - OH} \\ {|\,\,\,\,\,} \\ {\,\,\,\,{C_6}{H_3}} \end{array}\)
As language given, we have to go with option \((1)\) as stereochemistry of chiral centre is not distortet.
$CH _{3} CH = CHCH \left( CH _{3}\right)_{2} \stackrel{ HBr }{\longrightarrow}$
$X\xrightarrow[\Delta ]{{{H}_{2}}O}A+B+C+D$
$R - Br + C{l^ - }\xrightarrow{{DMF}}R - Cl + B{r^ - }$ ,
નીચેનામાંથી કઈ એક રૂપરેખાંકનનું સંપૂર્ણ વિપરીત પસાર કરે છે?
ઉપરોક્ત પ્રકિયા માં નીપજ $(P)$ શું હશે ?
$\xrightarrow{{NaN{H_2}}}\,A$
નીપજ $(A)$ શું હશે ?