$I.$ $C H_{3} C H=C H C H_{3}$ (મુખ્ય નીપજ )
$II.$ $C H_{2}=C H C H_{2} C H_{3}$ (ગૌણ નીપજ )
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,H} \\
{\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - CH - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow[{Alc.KOH}]{{ - {H_2}O}}$ $\left[ {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,H - OH} \\
{\,\,\,\,|} \\
{C{H_3}CH = CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \right] \to \mathop {C{H_3} - CH = CH - C{H_3}}\limits_{(Major\,product)} + B{r^ - }$
$(i)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}OH}}$ $ (CH_3)_2CH - CH_2OC_2H_5 + HBr$
$(ii)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}O^-}} $ $(CH_3)_2CH - CH_2OC_2H_5 + Br^-$
પ્રકિયા ની પદ્ધતિ $(i)$ અને $(ii)$ અનુક્રમે શું હશે ?
$(I)$ Benzylchloride
$(II)$ $p-$ Methoxy benzyl chloride
$(III)$ $p-$ Nitro benzyl chloride