\(= 4 \times 6.023 \times 10^{23}\) atoms
\(71.0\,gm\) of chlorine \( = \frac{{71.0}}{{71.0}} = 1\) moles of chlorine
\(= 6.023 \times 10^{23}\) atoms
\(127\,gm\) of iodine \( = \frac{1}{2}\) mole of \(I_2\)
\( = \frac{{127}}{{254}} = 6.023 \times {10^{23}} \times \frac{1}{2}\) atoms
\(48.0\,gm\) of magnesium
\( = \frac{{48.0}}{{24.0}} = 2 \times 6.023 \times {10^{23}}\) atoms
\(\therefore \) \(4.0\,gm\,H_2\) has largest number of atoms