$\overset{X}{\mathop{Mn}}\,{{\overset{-1}{\mathop{Cl}}\,}_{2}}:\,X+2\left( -1 \right)=0\,\Rightarrow X=+2$
$\overset{X}{\mathop{Mn}}\,{{\overset{-1}{\mathop{O}}\,}_{2}}:\,X+2\left( -2 \right)=0\,\Rightarrow X=+4$
$\overset{X}{\mathop{Mn}}\,{{\overset{-1}{\mathop{\left( OH \right)}}\,}_{3}}:\,X+3\left( -1 \right)=0\,\Rightarrow X=+3$
$\overset{+1}{\mathop{K}}\,\overset{X}{\mathop{Mn}}\,{{\overset{-2}{\mathop{O}}\,}_{4}}:\,\,1\left( +1 \right)+X+4\left( -2 \right)=0\,\Rightarrow X=+7$
આથી $Mn$ ના ઓ.આંકનો વધતો ક્રમ નીચે પ્રમાણે થશે.$MnC{l_2} < \,Mn{\left( {OH} \right)_3} < \,Mn{O_2} < KMn{O_4}$
${H_2}{O_2}\xrightarrow{{R.T}}{H_2}O + \frac{1}{2}{O_2}$
$\mathrm{Cr}_2 \mathrm{O}_7^{2-}+\mathrm{XH}^{+}+\mathrm{Ye}^{-} \rightarrow 2 \mathrm{~A}+\mathrm{ZH}_2 \mathrm{O}$
$\mathrm{X}, \mathrm{Y}, \mathrm{Z}$ અને $\mathrm{A}$ અનુક્કમે (ક્રમશઃ) શોધો.