નીચેના રૂપાંતરણ માટે યોગ્ય રીડકશનકર્તા કયો છે?

$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = CH - C{H_2} - C - H}
\end{array} \to C{H_3} - C{H_2} - C{H_2} - C{H_2}OH$

Question

નીચેના રૂપાંતરણ માટે યોગ્ય રીડકશનકર્તા કયો છે?

$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = CH - C{H_2} - C - H}
\end{array} \to C{H_3} - C{H_2} - C{H_2} - C{H_2}OH$

A$\operatorname{LiAlH}_{4 /} H _{2} O$
B$NaBH _{4} / H _{2} O$
C$Na + C _{2} H _{5} OH$
D$B_{2} H_{6} / H ^{+}$

AIIMS 2019, Diffcult

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Solution

d
$\operatorname{LiAlH}_{4} / H _{2} O , NaBH _{4} / H _{2} O$ and $Na / C _{2} H _{5} OH$ will reduce only $- CHO ,$ and not $C \equiv C$ bond.

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