(પ. ક્ર.: $Sc = 21 , Ti = 22, V = 23, Zn = 30$)
The electronic configuration of the given elements is
$S{c^{3 + }}(18)\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^0}\,4{s^0}$ no unpaired $e^-$
$T{i^{4 + }}(18)\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^0}\,4{s^0}$ no unpaired $e^-$
${V^{3 + }}(18)\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^2}\,4{s^0}$ - Two unpaired $e^-$.
$Z{n^{2 + }}(28)\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^{10}}\,4{s^0}$ no unpaired $e^-$
hence $[V(NH_3)_6]^{3+}$ will moost likely absorb visible light.
gly $=$ ગ્લાયસિનેટો; bpy $=2,2$ '-બાયપિરિડિન
સૂચિ $I$ (Complexes) | સૂચિ $II$ (Hybridisation) |
$A$ $\left[ Ni ( CO )_4\right]$ | $I$ $sp ^3$ |
$B$ $\left[ Cu \left( NH _3\right)_4\right]^{2+}$ | $II$ $dsp^2$ |
$C$ $\left[ Fe \left( NH _3\right)_6\right]^{2+}$ | $III$ $sp^3d^2$ |
$D$ $\left[ Fe \left( H _2 O \right)_6\right]^{2+}$ | $IV$ $d^2sp^3$ |
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