
$C{{H}_{3}}-C{{H}_{2}}-COOH\xrightarrow{PC{{l}_{3}}}I\xrightarrow{{{C}_{6}}{{H}_{6}}/AlC{{l}_{3}}}II\xrightarrow[\text{base/heat}]{N{{H}_{2}}-N{{H}_{2}}}III$
$CH \equiv CH$ $ \xrightarrow {CH_3MgBr}$ $ \xrightarrow {Co_2/H_3O^+}$ $ \xrightarrow {HgSO_4/H_2SO_4}$ $ \xrightarrow {Ag_2O,\Delta}$ $?$

