b \(S Cl_{4}\) is not isostructural with \(S i C l_{4}\) because shows square planar structure due to involvement of repulsion between lone pair and bond pair of electrons.
\(S O_{4}^{2-}\) shows tetrahedral structure due to \(s p^{3}\) hybridisation.
\(P O_{4}^{3-}\) shows tetrahedral structure due to \(s p^{3}\) hybridisation.
\(N H_{4}^{+}\) shows tetrahedral structure due to \(s p^{3}\) hybridisation.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*