In a network solid there are no individual molecules, and the entire crystal may be considered a macromolecule.
So in Diamond, \(\mathrm{SiO}_{2}\) atoms are bonded by covalent bonds in a continuous network extending throughout the material.
In a network solid there are no individual molecules, and the entire crystal may be considered a macromolecule.
Hence option D is correct.
$PH _{3}, B _{2} H _{6}, CCl _{4}, NH _{3}, LiH$ અને $BCl _{3}$.
$\mathrm{H}_2, \mathrm{He}_2^{+}, \mathrm{O}_2^{+}, \mathrm{N}_2^{2-}, \mathrm{O}_2^{2-}, \mathrm{F}_2, \mathrm{Ne}_2^{+}, \mathrm{B}_2$