c
The atomic size of Iodine is very big and it has empty \(d\) orbitals to expand it's electron in \(s\) and \(p\) orbitals In \(3^{\text {rd }}\) excited state iodine has \(7\) unpaired electrons so it can show positive oxidation state with higher electronegative element like \(Cl , Br , F\). Generally all halogens exhibit negative oxidation state due to their electronegativity.