સંકરણ $\to$ ભૂમિતિ $\to$ કક્ષકનો ઉપયોગ
$\therefore$ oplion $D$ is correctly matched.
In a trigonal bipyramidal geometry, the hybridisation is $sp^3d$. The orbitals are $s+P_x+P_y+P_z+d z^2$
so option $A$ is also correctly matched.
In a pentagonal bipyramidal geometry, the hybridisation is $sp^3d$ with steric number $=7$. The orbitals are $s+P_x+P_y+P_z+d x^2-y^2+d z^2+d x y$.
So option $B$ is also correctly matched.
In capped octahedral, the hybridisation is also $sp^3 d^3$.
So orbitals involved are $s+P_x+P_y+P_2+d x y+d_2{ }^2+d_x^2-y^2$.
$(I)\,$ $A$ની $s-$ કક્ષક અને $B$ની $P_x$ કક્ષક
$(II)\,$ $A$ની $s-$ કક્ષક અને $B$ની $P_z$ કક્ષક
$(Ill)\,$ $A$ની $p_y$ કક્ષક અને $B$ની $p_z$ કક્ષક
$(IV)\,$ $(A)$ અને $(B)$ની $s-$ કક્ષક
$(I) \,NCO^-$ $(II)\, CS_2$ $(III)\, \overset{+}{\mathop{N}}{{O}_{2}}$ $(IV)$ ઘન $BeH_2$