નીચેનામાંથી કયુ ખોટી રીતે સમાન થાય છે?

સંકરણ $\to$ ભૂમિતિ $\to$ કક્ષકનો ઉપયોગ

Question

નીચેનામાંથી કયુ ખોટી રીતે સમાન થાય છે?

સંકરણ $\to$ ભૂમિતિ $\to$ કક્ષકનો ઉપયોગ

A$sp^3d$ $ \to$ ત્રિકોણીય દ્વિપિરામિડલ $\to$ $s+P_x+P_y+P_z+d_{z^2}$
B$sp^3d^3$ $\to$ પંચકોણીય દ્વિપિરામિડલ $\to$ $s + P_x+P_y+P_z+d_{x^2-y^2} + d_{z^2} + d_{xy}$
C$sp^3d^3$ $\to$ અષ્ટફલકીય $\to$ $s + P_x + P_y + P_z + d_{x^2-y^2} +d_{z^2}$
D$sp^3$ $\to$ ચતુષ્ફલકીય $\to$ $s + P_x +P_y +P_z$

Medium

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Solution

c
In a tetra hedral geometry, the hybridisation is v. The orbitals in $sp^3$ are $s+p_x+p_y+p_z$.

$\therefore$ oplion $D$ is correctly matched.

In a trigonal bipyramidal geometry, the hybridisation is $sp^3d$. The orbitals are $s+P_x+P_y+P_z+d z^2$

so option $A$ is also correctly matched.

In a pentagonal bipyramidal geometry, the hybridisation is $sp^3d$ with steric number $=7$. The orbitals are $s+P_x+P_y+P_z+d x^2-y^2+d z^2+d x y$.

So option $B$ is also correctly matched.

In capped octahedral, the hybridisation is also $sp^3 d^3$.

So orbitals involved are $s+P_x+P_y+P_2+d x y+d_2{ }^2+d_x^2-y^2$.

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