ઉપર ની પ્રકિયાની નીપજ શું હશે ?

$C{H_2} = C{H_2}\xrightarrow[{oxid}]{{Hypochloro}}$ $M\xrightarrow{R}\begin{array}{*{20}{c}}
{C{H_2} - OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - OH}
\end{array}$
${C_2}{H_2}\xrightarrow[{HgS{O_4}/{H_2}S{O_4},60{\,^o}C}]{{{H_2}O}}X \rightleftharpoons C{H_3}CHO$