
$(I) \;CH_2 = CH - OH $
$(II)\; CH_2 = CH - CH_2OH$
$(III)\;CH_3 - CH_2 - OH$
$(IV)\; \begin{matrix} C{{H}_{3}}-CH-C{{H}_{3}} \\ |\,\,\,\, \\ OH \\ \end{matrix}$

${CH}_{4}+{I}_{2} \underset{\text { Reversible }}{\stackrel{{hv}}{\longrightarrow}} {CH}_{3}-{I}+{HI}$
