\(\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,} \\
{C{H_3} - C}
\end{array}\) \( —\leftarrow\) \(CH_2\) \( \rightarrow—\) \(\begin{array}{*{20}{c}}
{\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\) માં બે ઇલેકટ્રોન વીથડ્રોઈંગ સમૂહો ની આસપાસ છે જે તેને સક્રિય મિથીલીન સમૂહ બનાવે છે.
$A\xrightarrow[{(ii)\,\,Conc.\,{H_2}S{O_4}/\Delta }]{{{\text{(i)}}\,{\text{C}}{{\text{H}}_3}MgBr/{H_2}O}}$
$B\xrightarrow[{(ii)\,Zn/{H_2}O}]{{(i)\,{O_3}}}C + D$
$D\xrightarrow[\Delta ]{{Ba\left( {OH} \right)}}\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {{H_3}C - C} \end{array}$$\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,O} \\ {\,\,\,\,\,||} \\ { = CH - C - C{H_3}} \end{array}$
પ્રોપેનાલ , બેંઝાલ્ડીહાઈડ , પ્રોપેનોન , બ્યુટેનોન
(image) $\xrightarrow[{Pd - BaS{O_4}}]{{{H_2}}}\,A$
નીપજ $A$ શું હશે ?