$(x)\begin{array}{*{20}{c}}
{O\,\,\,}\\
{||\,\,\,}\\
{C{H_3} - S - O - H}\\
{||\,\,\,\,}\\
{O\,\,\,\,}
\end{array}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,O}\\
{\,\,\,\,\,\,||}\\
{(y)\,\,\,C{H_3} - C - O - H}
\end{array}$
$(z)\,\, CH_3 -OH$
\(\mathop {\begin{array}{*{20}{c}}
O \\
{||} \\
{Me - S - {O^\Theta }} \\
{||} \\
O
\end{array}}\limits_{3 - eq.\,R.S.} \) \(>\) \(\mathop {\begin{array}{*{20}{c}}
O \\
{||} \\
{Me - C - {O^\Theta }}
\end{array}}\limits_{2 - eq.\,R.S.} \) \(>\) \(Me - {O^\Theta }\)
So Acidic strength order is \(x>y>z\) so \(\mathrm{pK}_{\mathrm{a}}\) is \(z>y>x\)
$(1) H_3C - C = C⊝\,(2) H - C = C⊝ \,(3) $ ${H_3}C\,\, - \,\,\mathop C\limits^\Theta {H_2}$
નીચે આપેલા વિકલપોમાંથી સાચો જવાબ પસંદ કરો.
$a$ અને $b$ ની બંધ લંબાઈની તુલના કરો
