In \(\left[N i\left(P P h_{3}\right)_{2} C l_{2}\right]\) both the ilgands \(P P h^{3}\) and \(C 1\) are weak and as such cannot pair up the d-electrons. Thus hybridisation is \(s p^{3}\) and shape is tetrahedral.
$\operatorname{cis}-\left[\mathrm{Cr}(\mathrm{ox})_2 \mathrm{Cl}_2\right]^{3-},\left[\mathrm{Co}(\mathrm{en})_3\right]^{3+}$
$\operatorname{cis}-\left[\mathrm{Pt}(\mathrm{en})_2 \mathrm{Cl}_2\right]^{2+}, \text { cis }-\left[\mathrm{Co}(\mathrm{en})_2 \mathrm{Cl}_2\right]^{+}$
$\text {trans }-\left[\mathrm{Pt}(\mathrm{en})_2 \mathrm{Cl}_2\right]^{2+}, \text { trans }-\left[\mathrm{Cr}(\mathrm{ox})_2 \mathrm{Cl}_2\right]^{3-}$
$(I)\,K_3 [Fe(CN_6)]$ $(II)\, [Ni(CO)_4]^0$ $(III)\, [Cr(NH_3)_6]^{3+}$ $(IV)\, [Mn(CN)_6]^{4-}$
સાચો કોડ પસંદ કરો.
(મુક્ત $CO$ માં $C-O$ બંધલંબાઇ $1.128\,\mathop A\limits^o $ છે.
સૂચિ $-I$ | સૂચિ $-II$ |
$A$ $Ni ( CO )_{4}$ | $I$ $sp ^{3}$ |
$B$ ${\left[ Ni ( CN )_{4}\right]^{2-} }$ | $II$ $S p^{3} d^{2}$ |
$C$ ${\left[ Co ( CN )_{6}\right]^{3-} }$ | $III$ ${d^{2}}$ |
$D$ ${\left[ CoF _{6}\right]^{3-} }$ | $IV$ ${s p^{3}}{d s p^{2}}$ |
નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.