Explanation:
Since nitration and halogenation, both are carried out by the help of electrophile NO2+ & Cl+.
Hence, both reactions are electrophilic substitution reactions.
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$(i)\,\,C\,({\rm{graphite}})\, + \,{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = x\,\,kJ\,mo{l^{ - 1}}$
$(ii)\,\,C\,({\rm{graphite}})\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,CO\,(g);\,\Delta r{H^\circleddash} = y\,\,kJ\,mo{l^{ - 1}}$
$(iii)\,\,CO\,(g)\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = z\,\,kJ\,mo{l^{ - 1}}$
Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
$N_2(g) + 3H_2(g) \to 2NH_3(g)$ is
$-\,92.38\,KJ$ at $298\,K$ . The internal energy change $\Delta U$ at $298\,K$ is.....$KJ$