MCQ
Nitrogen can exhibit which of the following oxidation states:
- A$+1$
- B$+2$
- C$+3$
- ✓all of the above
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${C_6{H_5}N{H_2}}\xrightarrow{{{{(Ac)}_2}O}}$$X\xrightarrow{{B{r_2}/CC{l_4}}}Y\xrightarrow{{HOH}}Z$
Reason : Oxidation state of $Cr$ in $Na_2CrO_4$ is $+VI$