MCQ
Nitrogen is obtained when $NaN{O_2}$ reacts with
- ✓$N{H_4}Cl$
- B$N{H_4}N{O_3}$
- C${(N{H_4})_2}C{O_3}$
- D$N{H_4}OH$
$N{H_4}N{O_2} \longrightarrow {N_2} + 2{H_2}O$
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$A$ in the above reaction is:
[Given : Atomic mass of $H =1, C =12, N =14, O =16, S =32, Cl =35$ ]
(Rounded off to the nearest integer)