In this reaction \({1^o}\) carbonium ion is formed which rearranges to form \({3^o}\) carbonium ion from which base obstruct proton. Hence \(2-\) methyl-\(2\) -butene is formed as a main product.
\(\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - \mathop C\limits^ + {H_2}} \\
{|\,} \\
{\,\,\,\,\,\,C{H_{3\,\,}}}
\end{array}}\limits_{{1^o}\,carbonium\,less\,stable} \) \(\xrightarrow{{Methyl\,shift}}\begin{array}{*{20}{c}}
{C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\mathop {C{H_3} - C - C{H_2} - C{H_3}}\limits_ + }
\end{array}\)
\(\xrightarrow{{Elimination{\kern 1pt} of{\kern 1pt} proton{\kern 1pt} from{\kern 1pt} \beta {\kern 1pt} carbon{\kern 1pt} which{\kern 1pt} is{\kern 1pt} less{\kern 1pt} hydrogenated}}\mathop {\begin{array}{*{20}{c}}
{\,C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;}}} \\
{\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C = CH - C{H_3}}
\end{array}}\limits_{2 - Methyl - 2 - Butene} \)
$A$. સંયોજન '$B$' એરોમેટિક છે.
$B$. ઉપરની પ્રક્રિયા ખૂબ જ ધીમી પૂરી થાય છે.
$C$. '$A$' ચલરૂપક્તા દર્શાવે છે.
$D$. સંયોજન $B$ માં $C-C$ની બંધલંબાઈઓ સમાન મળી આવે છે.
નીચે આપેલા વિકલ્પોમાથી સાચો જવાબ પસંદ કરો.