In this reaction \({1^o}\) carbonium ion is formed which rearranges to form \({3^o}\) carbonium ion from which base obstruct proton. Hence \(2-\) methyl-\(2\) -butene is formed as a main product.
\(\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - \mathop C\limits^ + {H_2}} \\
{|\,} \\
{\,\,\,\,\,\,C{H_{3\,\,}}}
\end{array}}\limits_{{1^o}\,carbonium\,less\,stable} \) \(\xrightarrow{{Methyl\,shift}}\begin{array}{*{20}{c}}
{C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\mathop {C{H_3} - C - C{H_2} - C{H_3}}\limits_ + }
\end{array}\)
\(\xrightarrow{{Elimination{\kern 1pt} of{\kern 1pt} proton{\kern 1pt} from{\kern 1pt} \beta {\kern 1pt} carbon{\kern 1pt} which{\kern 1pt} is{\kern 1pt} less{\kern 1pt} hydrogenated}}\mathop {\begin{array}{*{20}{c}}
{\,C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;}}} \\
{\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C = CH - C{H_3}}
\end{array}}\limits_{2 - Methyl - 2 - Butene} \)
$(1)$ $CH_3 - C \equiv C - CH_3$ $(2)$ $CH_3CH_2CH_2CH_3$
$(3)$ $CH_3CH_2C \equiv CH$ $(4)$ $CH_3CH = CH_2$

| ઉદીપક | પ્રક્રિયા |
| $(i) \;\mathrm{Na}_{2} \mathrm{O}$ | $(a)$ ઇથાઈન માથી ઇથેનાલમાં ઓક્સિડેશન |
| $(ii) \;\mathrm{TiCl}_{4}+ \mathrm{Al(CH_3)}_{3}$ | $(b)$ આલ્કાઇન્સનું બહુલીકરણ |
|
$(iii)\;\mathrm{PdCl_2} $ |
$(c)$ $H_2SO_4$ની બનાવટમાં $SO_2$ના ઓક્સિડેશનમાં |
| $(iv)\;$ નિકલ સંકીર્ણો | $(d)$ ઇથિલીનનું બહુલીકરણ |
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