MCQ
No. of $\pi$ electrons in the following is :
- A$2$
- B$4$
- C$5$
- ✓$6$
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Product $(A)$ is
$\begin{array}{l}{C_6}{H_5}C{H_3},\\\,\,\,\,\,\,\,\,\,\,{\rm{I}}\end{array}$$\begin{array}{l}{C_6}{H_5}COOH,\\\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{II}}\end{array}$$\begin{array}{l}{C_6}{H_6}\\\,\,\,\,{\rm{III}}\end{array}$$\begin{array}{l}{C_6}{H_5}N{O_2}\\\,\,\,\,\,\,\,\,\,\,{\rm{IV}}\end{array}$
$ 2 \mathrm{~S}_2 \mathrm{O}_3^{2-}+\mathrm{I}_2 \rightarrow \mathrm{S}_4 \mathrm{O}_6^{2-}+2 \mathrm{I}^{-}$
$\mathrm{S}_2 \mathrm{O}_3^{2-}+5 \mathrm{Br}_2+5 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{SO}_4^{2-}+4 \mathrm{Br}^{-}+10 \mathrm{H}^{+}$
Which of the following statement justifies the above dual behaviour of thiosulphate?