MCQ
Normal butane convert into isobutane by
  • A
    $LiAl{H_4}$
  • $AlC{l_3}$
  • C
    $NaB{H_4}$
  • D
    $Zn / HCl$

Answer

Correct option: B.
$AlC{l_3}$
b
(b) $\mathop {C{H_3}C{H_2}C{H_2}C{H_3}}\limits_{n - {\rm{butane}}}  \xrightarrow[\Delta]{Anhyd AlCl_3}  \mathop {C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,\,}\limits_{\,\,C{H_3}} }  - C{H_3}}\limits_{{\rm{iso}}\,{\rm{butane}}} $

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