\( \therefore\) Frequency of pipe \(= 200 \pm \,5 = 195 Hz\) or \(205 Hz\) ...\((i)\)
Frequency of second harmonics of the pipe \(= 2n\)
and number of beats in this case \(= 10\)
\( \therefore\) \(2n = 420 \pm \, 10 \)
==> \(410 Hz\) or \(430 Hz\)
==> \(n = 205 Hz\) or \(215 Hz\) ... \((ii)\)
From equation \((i)\) and \((ii)\) it is clear that \(n = 205 Hz\)
$\left(\mathrm{R}=8.3 \mathrm{JK}^{-1}, \gamma=1.4\right.$આપેલ છે.)