MCQ
Number of angular nodes for 4d orbital is __________.
- A4.
- B3
- C2.
- D1.
Explanation:
Number of radial nodes in any orbital = (n - l - 1)
= (4 - 2 - 1) = 1
Total number of nodes = ( n - 1 )
= (4 - 1) = 3
So angular node = total node - radial node
= (3 - 1) = 2.
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${A_2}B(g) \to {A_2}(g) + B(g);\,\,\,\Delta {H^o} = 40\,kJ/mol$
${A_2}B(g) \to A(g) + AB(g);\,\,\,\Delta {H^o} = 50\,kJ/mol$
.....$ kJ/mol$