MCQ
Number of $\pi $ bonds in $C{H_2} = CH - CH = CH - C \equiv CH$ is
- A$2$
- B$3$
- ✓$4$
- D$5$
✓
Answer
Correct option: C.
$4$
c
| Nature of bond | Number of sigma bonds | Number of pi-bonds |
| Single bond | $1$ | $0$ |
| Double bond | $1$ | $1$ |
| Triple bond | $1$ | $2$ |
In the compound $CH _2= CH - CH = CH - C \equiv CH$,
there are $(2 \times 1)+(1 \times 2)$
$=4$ pi-bonds in total.
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