MCQ
If $M$ is the molecular weight of $KMn{O_4}$, its equivalent weight will be when it is converted into ${K_2}Mn{O_4}$
- ✓$M$
- B$M/3$
- C$M/5$
- D$M/7$
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$\mathrm{MnO}_{4}^{-}+\mathrm{C}_{2} \mathrm{O}_{4}^{2-}+\mathrm{H}^{+} \longrightarrow \mathrm{Mn}^{2+}+\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O}$
the correct coefficients of the reactants for the balanced equation are
$\mathrm{MnO}_{4}^{-} \quad \mathrm{C}_{2} \mathrm{O}_{4}^{2-}\quad \mathrm{H}^{+}$

