Objective of LPP is: 1. A constraint 2. A function to be optimize… - Vidyadip

Question

Objective of LPP is:

A constraint
A function to be optimized
A relation between the variables
None of the above

✓

Answer

A function to be optimized

Solution:
The objective of Linear Programming Problems (LPP) is to minimize or maximize the function.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Programming→Linear Programming — all question types→MATHS STD 12 Science question papers→Rajasthan Board STD 12 Science question papers→Rajasthan Board question paper generator→

Similar questions

The position of origin $(0,0)$ w.r.t. feasible region represented by $x+y \geq 1$ is

Find the matrix $A^2$, where $A=\left[a_{i j}\right]$ is a $2 \times 2$ matrix whose elements are given by $a_{i j}=$ maximum $(i, j)-$ minimum $(i, j)$ :

The value of $\int \frac{\sec x}{\operatorname{cosec}^2 x} d x$

The value of the determinant $\left|\begin{array}{ccc}2 & 7 & 1 \\ 1 & 1 & 1 \\ 10 & 8 & 1\end{array}\right|$ is

Let $A = \{1, 2, 3, …. n\}$ and $B = \{a, b\}.$ Then the number of surjections from $A$ into $B$ is$:$

If $f : R \rightarrow R$ be given by $f(\text{x})=(3-\text{x}^3)^{\frac{1}{3}},$ then $fof(x)$ is :

If $\vec{\text{a}}=2\hat{\text{i}}-3\hat{\text{j}}-\hat{\text{k}}$ and $\vec{\text{b}}=\hat{\text{i}}+4\hat{\text{j}}-2\hat{\text{k}},$ then $\vec{\text{a}}\times\vec{\text{b}}$ is:

$10\hat{\text{i}}+2\hat{\text{j}}+11\hat{\text{k}}$
$10\hat{\text{i}}+3\hat{\text{j}}+11\hat{\text{k}}$
$10\hat{\text{i}}-3\hat{\text{j}}+11\hat{\text{k}}$
$10\hat{\text{i}}-2\hat{\text{j}}-10\hat{\text{k}}$

If $A$ is a square matrix of order $3$ such that the value of $|\operatorname{adj} A|=8,$ then the value of $\left|A^{\top}\right|$ is

The direction cosines of the normal to the plane 2x - 3y - 6z - 3 = 0 are:

$\frac{2}{7},\frac{-3}{7},\frac{-6}{7}$
$\frac{2}{7},\frac{3}{7},\frac{6}{7}$
$\frac{-2}{7},\frac{-3}{7},\frac{-6}{7}$
None of these

Matrices A and B will be inverse of each other only if:

AB = BA
AB = BA = 0
AB = 0, BA = I
AB = BA = I