Question
Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th second.
✓
Answer
Using the equation of motion $\text{s}=\text{ut}+\frac{1}{2}\text{at}^{2}$ Distance travelled in 5 seconds, $\text{s}=\text{u}\times5+\frac{1}{2}\text{a}\times5^{2}$ or $\text{s}=5\text{u}+\frac{25}{2}\text{a}$ Similary, distance travelled in 4seconds, $\text{s}=4\text{u}+\frac{16}{2}\text{a}$ Distance travelled in the interval between $4th$ and $5th$ seconds$=(\text{s-s'})=(\text{u}+\frac{9}{2}\text{a})\text{m}$
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Show by using the graphical method that:$\text{s}=\text{ut}+\frac{1}{2}\text{at}^2$
where the symbols have their usual meanings.
→where the symbols have their usual meanings.
Show by using the graphical method that:
$\text{s}=\text{ut}+\frac{1}{2}\text{at}^2$
where the symbols have their usual meanings.
→$\text{s}=\text{ut}+\frac{1}{2}\text{at}^2$
where the symbols have their usual meanings.