Obtain Nernst equation for the electrode potential for the electr… - Vidyadip

Question

Obtain Nernst equation for the electrode potential for the electrode, $Zn _{( aq )}^{2+} \mid Zn _{( s )}$.

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Answer

For the electrode, $Zn _{( aq )}^{2+} \mid Zn _{( s )}$,
the reduction reaction is,
$Zn _{\text {(aq) }}^{2+}+2 e ^{-} \longrightarrow Zn _{( s )} \therefore n =2$
By Nernst equation, the reduction electrode potential is given by,
$\begin{aligned}
& E_{ Zn ^{2+} / Zn }=E^0_{ Zn ^{2+} / Zn }-\frac{0.0592}{2} \log _{10} \frac{1}{\left[ Zn ^{2+}\right]} \\
=& E_{ Zn ^{2+} / Zn }+\frac{0.0592}{2} \log _{10}\left[ Zn ^{2+}\right] \\
&
\end{aligned}$
where $E ^0 zn ^{2+} / zn$ is the standard electrode potential of zinc electrode.

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