Maharashtra BoardEnglish MediumSTD 12 ScienceChemistrySolutions2 Marks
Question
Obtain the units of Henry’s law constant.
✓
Answer
By Henry's law, $S=K_H \times P$, where $S$ is solubility of the gas in mol $dm ^{-3}, P$ is the pressure of the gas in atmosphere (or in bar) and $K _{ H }$ is Henry's law constant. $\therefore K _{ H }=\frac{S^{\left( moldm ^{-3}\right)}}{P_{( atm )}} mol dm atm ^{-1}$ or $mol dm ^{-3} bar ^{-1}$ Hence the units of Henry's law constant $K _{ H }$ are $mol dm { }^{-3} atm ^{-1}$.
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