Question
Obtain the values of : ${ }^{10} P_{2}$

Answer

${ }^{10} \mathrm{P}_2=\frac{10 !}{(10-3) !}$
$ =\frac{10 !}{7 !}$
$ =\frac{10 \times 9 \times 8 \times 7 !}{7 !}$
$ =10 \times 9 \times 8=720$
$ \therefore{ }^{10} \mathrm{P}_2=720$
Alternative method:
${ }^{10} \mathrm{P}_2=10(10-1)(10-2)$
$ =10 \times 9 \times 8=720$
$ \therefore{ }^{10} \mathrm{P}_2=720$

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